(2,5x^2)/(0,5x^-0,5)=20

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Solution for (2,5x^2)/(0,5x^-0,5)=20 equation: 


D( x )

x < 0

x = 0

0.5*x^-0.5 = 0

x < 0

x = 0

x = 0

0.5*x^-0.5 = 0

0.5*x^-0.5 = 0

0.5*x^-0.5 = 0 // : 0.5

x^-0.5 = 0

x należy do O

x in (0:+oo)

(2.5*x^2)/(0.5*x^-0.5) = 20 // - 20

(2.5*x^2)/(0.5*x^-0.5)-20 = 0

5*x^2.5 = 20 // : 5

x^2.5 = 4

x^2 = 4^(1/0.5) // ^ 1/2

abs(x) = 4

x = 4 or x = -4

x in { -4} 

x = 4

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